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120=5x+1.5x^2
We move all terms to the left:
120-(5x+1.5x^2)=0
We get rid of parentheses
-1.5x^2-5x+120=0
a = -1.5; b = -5; c = +120;
Δ = b2-4ac
Δ = -52-4·(-1.5)·120
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{745}}{2*-1.5}=\frac{5-\sqrt{745}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{745}}{2*-1.5}=\frac{5+\sqrt{745}}{-3} $
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